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<title>Vol. 21, No.1</title>
<link>http://tainguyenso.vnu.edu.vn/jspui/handle/123456789/88</link>
<description/>
<pubDate>Mon, 18 May 2026 10:52:15 GMT</pubDate>
<dc:date>2026-05-18T10:52:15Z</dc:date>
<item>
<title>Problè me gé né ral aux limites de Riemann avec dé placement et probl\è me de Hilbert pour l'e'xté rieur domain de l'unitaire circle</title>
<link>http://tainguyenso.vnu.edu.vn/jspui/handle/123456789/446</link>
<description>Problè me gé né ral aux limites de Riemann avec dé placement et probl\è me de Hilbert pour l'e'xté rieur domain de l'unitaire circle
Vu, Van Khuong
Dans le livre ”probl`eme aux limites” de prof. Ph. D. Gakhov (voir [1]), on a&#13;
r´esolu les trois probl`emes suivants:&#13;
+ Probl`eme aux limites de Riemann&#13;
Φ+(t) =&#13;
&#1048579;μ&#13;
k=1(t − αk)mk&#13;
&#1048579;ν&#13;
j=1(t − βj)pj&#13;
G1(t)Φ−(t), (1)&#13;
o`u αk (k = 1, μ), βj (j = 1, ν) sont des quelconques points sur la fronti`ere L; mk, pj&#13;
des entiers positifs. G1(t) est la fonction diff´erente de z´ero pour tout t ∈ L, satisfaisante&#13;
`a condition de Holder.&#13;
+ Probl`eme g´en´eral aux limites de Riemann avec d´eplacement&#13;
Φ+[α(t)] = G(t)Φ−(t). (2)&#13;
+ Probl`eme de Hilbert pour la circonf´erence int´erieure D+ de l’unitaire circle.&#13;
Dans cet article nous consid´erons les trois probl`emes g´en´eralis´es (en correspondance) suivants.&#13;
+ Probl`eme de Riemann satisfaisant `a l’´equation (1) et aux conditions de Cauchy&#13;
dkΦ(zh)&#13;
dzk = ahk&#13;
, k = 1,mh − 1, h = 1, n.&#13;
+ Probl`eme g´en´eral aux limites de Riemann avec d´eplacement&#13;
Φ+[α(t)] =&#13;
&#1048579;μ&#13;
k=1(t − αk)mk&#13;
&#1048579;ν&#13;
j=1(t − βj)pj&#13;
G(t)Φ−(t).&#13;
+ Probl`eme de Hilbert pour la circonf´erence ´ext´erieure D− de l’unitaire circle.
VNU. JOURNAL OF SCIENCE, Mathematics - Physics. Vol. 21, No. 1 - 2005
</description>
<pubDate>Sat, 01 Jan 2005 00:00:00 GMT</pubDate>
<guid isPermaLink="false">http://tainguyenso.vnu.edu.vn/jspui/handle/123456789/446</guid>
<dc:date>2005-01-01T00:00:00Z</dc:date>
</item>
<item>
<title>Non-linear analysis of multilayered reinforced composite plates</title>
<link>http://tainguyenso.vnu.edu.vn/jspui/handle/123456789/444</link>
<description>Non-linear analysis of multilayered reinforced composite plates
Khuc, Van Phu; Pham, Tien Dat
This paper deals with the analysis of non-linaer multilayered reinforced composite&#13;
plates with simply supported along its four edges by Bubnov - Galerkin and Finite&#13;
Element Methods. Numerical results are presented for illustrating theoretical analysis of&#13;
reinforced and unreinforced laminated composite plates.
VNU. JOURNAL OF SCIENCE, Mathematics - Physics. Vol. 21, No. 1 - 2005
</description>
<pubDate>Sat, 01 Jan 2005 00:00:00 GMT</pubDate>
<guid isPermaLink="false">http://tainguyenso.vnu.edu.vn/jspui/handle/123456789/444</guid>
<dc:date>2005-01-01T00:00:00Z</dc:date>
</item>
<item>
<title>The magnetic properties and charge-ordering state in La1-xCaxMnO3 (x = 0.46; 0.50) compounds</title>
<link>http://tainguyenso.vnu.edu.vn/jspui/handle/123456789/441</link>
<description>The magnetic properties and charge-ordering state in La1-xCaxMnO3 (x = 0.46; 0.50) compounds
Nguyen, Huy Sinh; Vu, Thanh Mai; Nguyen, Anh Tuan; Pham, Hong Quang; Nguyen, Tuan Son
The compounds of La1-xCaxMnO3-δ with x=0.46 and 0.50 occupy special&#13;
positions in the phase diagram of La1-xCaxMnO3-δ system due to their interesting&#13;
properties and charge-ordering phase transition. The samples were prepared by a&#13;
solid-state reaction method. The XPD patterns show that the samples are of a&#13;
single-phase orthorhombic-perovskite structure. The chemical compositions of the&#13;
samples are investigated by EDS. The concentrations of oxygen and Mn3+; Mn4+ ions&#13;
have been determined by dichromate method. The charge-ordering state have been&#13;
found below 150 K by magnetic and resistance measurements. This phenomenon&#13;
relates to metal-insulator transition. The results are discussed in competition&#13;
between double exchange (DE) and super-exchange (SE) interaction
VNU. JOURNAL OF SCIENCE, Mathematics - Physics. Vol 21, No. 1, 2005
</description>
<pubDate>Sat, 01 Jan 2005 00:00:00 GMT</pubDate>
<guid isPermaLink="false">http://tainguyenso.vnu.edu.vn/jspui/handle/123456789/441</guid>
<dc:date>2005-01-01T00:00:00Z</dc:date>
</item>
<item>
<title>Local dimension of fractal measure associated with the $(0, 1, a)$ - problem: the case $a = 6$</title>
<link>http://tainguyenso.vnu.edu.vn/jspui/handle/123456789/437</link>
<description>Local dimension of fractal measure associated with the $(0, 1, a)$ - problem: the case $a = 6$
Le, Xuan Son; Pham, Quang Trinh; Vu, Hong Thanh
Let X1,X2, ... be a sequence of independent, identically distributed(i.i.d)&#13;
random variables each taking values 0, 1, a with equal probability 1/3. Let μ be the&#13;
probability measure induced by S =&#13;
&#1048607;&#13;
∞n&#13;
=1 3−nXn. Let α(s) (resp.α(s), α(s)) denote&#13;
the local dimension (resp. lower, upper local dimension) of s ∈ supp μ, and let&#13;
α = sup{α(s) : s ∈ supp μ}; α = inf{α(s) : s ∈ supp μ}&#13;
E = {α : α(s) = α for some s ∈ supp μ}.&#13;
In the case a = 3, E = [2/3, 1], see [6]. It was hoped that this result holds true with&#13;
a = 3k, for any k ∈ N. We prove that it is not the case. In fact, our result shows&#13;
that for k = 2(a = 6), α = 1, α = 1 − log(1+√5)−log 2&#13;
2 log 3 ≈ 0.78099 and E = [1 −&#13;
log(1+√5)−log 2&#13;
2 log 3 , 1].Let X1,X2, ... be a sequence of independent, identically distributed(i.i.d)&#13;
random variables each taking values 0, 1, a with equal probability 1/3. Let μ be the&#13;
probability measure induced by S =&#13;
&#1048607;&#13;
∞n&#13;
=1 3−nXn. Let α(s) (resp.α(s), α(s)) denote&#13;
the local dimension (resp. lower, upper local dimension) of s ∈ supp μ, and let&#13;
α = sup{α(s) : s ∈ supp μ}; α = inf{α(s) : s ∈ supp μ}&#13;
E = {α : α(s) = α for some s ∈ supp μ}.&#13;
In the case a = 3, E = [2/3, 1], see [6]. It was hoped that this result holds true with&#13;
a = 3k, for any k ∈ N. We prove that it is not the case. In fact, our result shows&#13;
that for k = 2(a = 6), α = 1, α = 1 − log(1+√5)−log 2&#13;
2 log 3 ≈ 0.78099 and E = [1 −&#13;
log(1+√5)−log 2&#13;
2 log 3 , 1].
VNU. JOURNAL OF SCIENCE, Mathematics - Physics. Vol.21 , No 1 - 2005
</description>
<pubDate>Sat, 01 Jan 2005 00:00:00 GMT</pubDate>
<guid isPermaLink="false">http://tainguyenso.vnu.edu.vn/jspui/handle/123456789/437</guid>
<dc:date>2005-01-01T00:00:00Z</dc:date>
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